2209.15124
ROCHBERG’S ABSTRACT COBOUNDARY THEOREM REVISITED
Catalin Badea, Oscar Devys
correctmedium confidence
- Category
- Not specified
- Journal tier
- Specialist/Solid
- Processed
- Sep 28, 2025, 12:56 AM
- arXiv Links
- Abstract ↗PDF ↗
Audit review
The paper proves Theorem 1.4: for an isometry T and x with ∑_{k≥0} k ||T^{*k}x|| < ∞, x is a coboundary (x = (I−T)y) iff (1/n)||∑_{k=0}^{n} T^k x||^2 → 0. The proof reduces via Wold decomposition to the shift part and constructs y = ∑_r y_r with y_r := ∑_{k=0}^r T^k x_{r−k}, then shows ∑_r ||y_r||^2 < ∞ using two lemmas (a limit identity under ∑ ||T^{*j}u|| < ∞ and a projection/Fejér-type identity), which together yield the required estimates in terms of ∑ k ||T^{*k}x|| (the given assumption) . By contrast, the model’s Phase 2 argument leaves critical gaps: (i) it asserts a Hilbert-valued Hardy inequality to uniformly bound the Fejér approximants y^(N) but does not provide a valid bound under the paper’s hypothesis, and it incorrectly treats sup_n (1/n)||S_n x||^2 as uniformly bounded merely from its limit 0 (limit→0 does not imply bounded sup); (ii) it tries to control ∑_k k||d_k||^2 from ∑_k k||T^{*k}x||, but the needed implication (essentially ∑ ||T^{*k}x||^2 < ∞) is not justified under the paper’s weaker assumption. The paper’s construction avoids these pitfalls by a different decomposition-and-estimate route. Therefore the paper is correct; the model’s solution is incomplete/incorrect on key estimates.
Referee report (LaTeX)
\textbf{Recommendation:} minor revisions \textbf{Journal Tier:} specialist/solid \textbf{Justification:} The main isometric-case theorem is proved cleanly and self-containedly, with a construction that leverages Wold decomposition and precise estimates tied to the summability of backward iterates. The argument handles the delicate \$(b)\Rightarrow(a)\$ direction without imposing unnecessary square-summability, using two tailored lemmas. The exposition could benefit from minor clarifications, but overall the manuscript is correct and useful.