2406.00733
Elementary solution to the fair division problem
Michael Blank, Maxim Polyakov
correctmedium confidence
- Category
- Not specified
- Journal tier
- Specialist/Solid
- Processed
- Sep 28, 2025, 12:56 AM
- arXiv Links
- Abstract ↗PDF ↗
Audit review
The paper proves an envy-free (strong) division for atomless charges via an explicit iterative scheme that carves out, at each macro-step, a sizeable subset H on which a strong solution exists, and shows exponential decay of the remainder with respect to the summed measure µ = Σi µi, namely µ(Ms) ≤ ((2^{r−1}−1)/2^{r−1})^s µ(M) for the measures case, and an analogous decay in the charges case, stitching positive/negative parts through Hahn–Jordan and a gentleman’s division construction. These claims are established in Theorem 2.1 and the constructions of Sections 5–6, with the decay bound explicitly derived in Corollary 5.3 and Lemma 6.5/Corollary 6.6 . The model solution gives a different, Lyapunov-based “equal-clone” algorithm: repeatedly halve vector measures to create 2^{r−1} equal clones and assign r of them each round; this yields a stronger property (exact division from every agent’s perspective, not just envy-freeness) and a sharper rate (for measures, 1−r/2^{r−1} per round). Both approaches rely on atomlessness and Lyapunov convexity (explicitly assumed or invoked) and are coherent. Thus, both are correct, with substantially different constructions and quantitative guarantees.
Referee report (LaTeX)
\textbf{Recommendation:} minor revisions \textbf{Journal Tier:} specialist/solid \textbf{Justification:} The manuscript delivers a clear, explicit algorithm for envy-free division in the measure-theoretic setting, extends it to atomless charges, and proves exponential convergence. The main ideas are sound and grounded in standard results (Hahn–Jordan, Lyapunov). Some steps could be expanded for readability, and the status of the “explicit subset” assumption could be highlighted. With minor clarifications and a couple of illustrative examples, the paper would be a solid contribution.