2410.01267
INTERIOR OF CERTAIN SUMS AND CONTINUOUS IMAGES OF VERY THIN CANTOR SETS
Yeonwook Jung, Chun-Kit Lai
wronghigh confidenceCounterexample detected
- Category
- math.DS
- Journal tier
- Specialist/Solid
- Processed
- Sep 28, 2025, 12:56 AM
- arXiv Links
- Abstract ↗PDF ↗
Audit review
The paper’s Theorem 1.1 asserts that for any Cantor set K1 and any C^1 map H(α,x,y) with invertible Jacobian in the y-variable, there exists a Cantor set K2 and a parameter cube such that the intersection over all parameters of H(α,K1,K2) has nonempty interior (Theorem 1.1 and its restatement as Theorem 5.5) . However, taking H(α,x,y)=y satisfies the paper’s hypotheses (JH,2 is the identity), yet yields H(α,K1,K2)=K2 for all α, so the intersection is K2, which, being a Cantor set, has empty interior. Thus the theorem is false as stated. The proof contains a critical error: after using the implicit function theorem to define gc,α, the paper claims Jgc,α=JH,2^{-1}JH,1 is invertible “by our assumption” (that JH,2 is invertible) . This inference is invalid unless JH,1 is also invertible (or has full rank). In the counterexample H=y, JH,1=0 so Jgc,α=0, contradicting the claimed invertibility and breaking the subsequent argument. The model’s counterexample is therefore correct and exposes the flaw.
Referee report (LaTeX)
\textbf{Recommendation:} reject \textbf{Journal Tier:} specialist/solid \textbf{Justification:} The flagship theorem is false under the stated hypotheses. The proof makes a critical and unjustified leap by asserting the invertibility of Jg\_{c,α} from invertibility of J\_{H,2}. A simple counterexample H(α,x,y)=y meets the paper’s assumptions yet contradicts the conclusion, showing no choice of Cantor K2 can produce interior. While the supporting machinery (containment and non-degeneracy ideas) is interesting and potentially valuable, the main result requires substantive changes in assumptions and a reworked proof.